dc.contributorMorán, Diego
dc.date.accessioned2021-11-23T12:07:56Z
dc.date.accessioned2022-11-08T20:35:46Z
dc.date.available2021-11-23T12:07:56Z
dc.date.available2022-11-08T20:35:46Z
dc.date.created2021-11-23T12:07:56Z
dc.identifierhttps://repositorio.uai.cl//handle/20.500.12858/2751
dc.identifier10.1007/s10107-019-01379-y
dc.identifier.urihttps://repositorioslatinoamericanos.uchile.cl/handle/2250/5147382
dc.description.abstractGiven P ⊂ Rn, a mixed-integer set PI = P ∩ (Zt × Rn−t ), and a k-tuple of n_x005F_x0002_dimensional integral vectors (π1,...,πk ) where the last n − t entries of each vector is zero, we consider the relaxation of PI obtained by taking the convex hull of points x in P for which πT 1 x,...,πT k x are integral. We then define the k-dimensional lattice closure of PI to be the intersection of all such relaxations obtained from k-tuples of n-dimensional vectors. When P is a rational polyhedron, we show that given any collection of such k-tuples, there is a finite subcollection that gives the same closure; more generally, we show that any k-tuple is dominated by another k-tuple coming from the finite subcollection. The k-dimensional lattice closure contains the convex hull of PI and is equal to the split closure when k = 1. Therefore, a result of Cook et al. (Math Program 47:155–174, 1990) implies that when P is a rational polyhedron, the k-dimensional lattice closure is a polyhedron for k = 1 and our finiteness result extends this to all k ≥ 2. We also construct a polyhedral mixed-integer set with n integer variables and one continuous variable such that for any k < n, finitely many iterations of the k-dimensional lattice closure do not give the convex hull of the set. Our result implies that t-branch split cuts cannot give the convex hull of the set, nor can valid inequalities from unbounded, full-dimensional, convex lattice-free sets
dc.titleLattice closures of polyhedra.
dc.typeArtículo Scopus


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